Two Pointer
Two pointer 有两种解法:
1)l = 0, r = n - 1,两指针相向而行
2)l = 0, r = 1,两指针同向而行
经典题目
// 两指针相向而行
public int triangleNumber(int[] nums) {
Arrays.sort(nums);
int ans = 0;
for(int l = 2; l < nums.length; l++) {
int i = 0, j = l - 1;
while (i < j) {
if (nums[i] + nums[j] > nums[l]) {
ans += j - i;
j--;
} else {
i++;
}
}
}
return ans;
}15 3Sum (with Dedup)
Last updated